Solution: Let x be the amount of milk the first cow produced during the first year.

Then the second cow produced $(8100 - x)$ litres of milk that year.

Therefore in 5 days they ploughed $5 \cdot 4 \cdot x = 20 \cdot x$ hectares, which equals the area of the whole field, 2880 hectares. Hence, each of the four tractors would plough 144 hectares a day.

Problem 7 The distance between two towns is 380 km.

In the right triangle ABC the side which is opposite to angle 50 degree is known as opposite side (AB), the side which is opposite to 90 degree is called hypotenuse side (AC) and remaining side is called adjacent side (BC). From the figure given above, AB stands for the height of the airplane above the ground.

sin θ = Opposite side/Hypotenuse sidesin 50° = AB/AC0.7660 = h/120.7660 x 12 = hh = 9.192 km So, the height of the airplane above the ground is 9.192 km.

That is, we have to find the length of θ = Opposite side/Adjacent sidetan60° = AB/BC√3 = 6/BCBC = 6/√3BC = (6/√3) x (√3/√3)BC = (6√3)/3BC = 2√3Approximate value of √3 is 1.732BC = 2 (1.732)BC = 3.464 m Here AB represents height of kite from the ground, BC represents the distance of kite from the point of observation.

In the right triangle ABC the side which is opposite to angle 60 degree is known as opposite side (AB), the side which is opposite to 90 degree is called hypotenuse side (AC) and remaining side is called adjacent side (BC). Sin θ = Opposite side/Hypotenuse sidesinθ = AB/ACsin 60° = AB/100√3/2 = AB/100(√3/2) x 100 = ABAB = 50 √3 m So, the height of kite from the ground 50 √3 m.

In the right triangle ABC, the side which is opposite to angle 60 degree is known as opposite side (AB), the side which is opposite to 90 degree is called hypotenuse side (AC) and remaining side is called adjacent side (BC).

Now, we need to find the distance between foot of the ladder and the wall.

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