# Algebra Problems To Solve

$$a=r\cdot b\Rightarrow Percent=Rate\cdot Base$$ Where the base is the original value and the percentage is the new value.Example 47% of the students in a class of 34 students has glasses or contacts.Or click the "Show Answers" button at the bottom of the page to see all the answers at once.

$$a=r\cdot b\Rightarrow Percent=Rate\cdot Base$$ Where the base is the original value and the percentage is the new value.Example 47% of the students in a class of 34 students has glasses or contacts.Or click the "Show Answers" button at the bottom of the page to see all the answers at once.

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Solving Algebra word problems is useful in helping you to solve earthly problems.

While the 5 steps of Algebra problem solving are listed below, this article will focus on the first step, Identify the problem.

Solving word problems is an art of transforming the words and sentences into mathematical expressions and then applying conventional algebraic techniques to solve the problem.

They may involve a single person, comparing his/her age in the past, present or future.

They may also compare the ages involving more than one person.

$0-150=90$$Then we find out how many percent this change corresponds to when compared to the original number of students$$a=r\cdot b$$=r\cdot 150$$ $$\frac=r$$$[[

They may also compare the ages involving more than one person.

$$240-150=90$$ Then we find out how many percent this change corresponds to when compared to the original number of students $$a=r\cdot b$$ $$90=r\cdot 150$$ $$\frac=r$$ $$0.6=r= 60\%$$ We begin by finding the ratio between the old value (the original value) and the new value $$percent\:of\:change=\frac=\frac=1.6$$ As you might remember 100% = 1.

Since we have a percent of change that is bigger than 1 we know that we have an increase.

To find out how big of an increase we've got we subtract 1 from 1.6.

This article was co-authored by our trained team of editors and researchers who validated it for accuracy and comprehensiveness. Deborah has $88.50, and Colin has$61.50, which together add up to $150. || They may also compare the ages involving more than one person.$$240-150=90$$ Then we find out how many percent this change corresponds to when compared to the original number of students $$a=r\cdot b$$ $$90=r\cdot 150$$ $$\frac=r$$ $$0.6=r= 60\%$$ We begin by finding the ratio between the old value (the original value) and the new value $$percent\:of\:change=\frac=\frac=1.6$$ As you might remember 100% = 1.Since we have a percent of change that is bigger than 1 we know that we have an increase.To find out how big of an increase we've got we subtract 1 from 1.6.This article was co-authored by our trained team of editors and researchers who validated it for accuracy and comprehensiveness. Deborah has$88.50, and Colin has $61.50, which together add up to$150.Together, they cited information from 10 references. wiki How's Content Management Team carefully monitors the work from our editorial staff to ensure that each article meets our high quality standards. You can solve many real world problems with the help of math. To solve problems with percent we use the percent proportion shown in "Proportions and percent".$$\frac=\frac$$ $$\frac\cdot =\frac\cdot b$$ $$a=\frac\cdot b$$ x/100 is called the rate.Break the problem down into smaller bits and solve each bit at a time.First, we need to translate the word problem into equation(s) with variables.

]].6=r= 60\%$$We begin by finding the ratio between the old value (the original value) and the new value$$percent\:of\:change=\frac=\frac=1.6 As you might remember 100% = 1.

Since we have a percent of change that is bigger than 1 we know that we have an increase.

To find out how big of an increase we've got we subtract 1 from 1.6.

This article was co-authored by our trained team of editors and researchers who validated it for accuracy and comprehensiveness. Deborah has .50, and Colin has .50, which together add up to 0.

## Comments Algebra Problems To Solve

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